Solution to Beaux Taurus

Once the pieces are cut out, assembling them into the labyrinth proceeds in two stages:

Squares assembled

The half-squares are assembled in pairs into squares, by assembling each mintotaur (figure with bull horns and human feet) so the "horns" clue answer is the "feet" clue answer with MOO or LOW added. The set of squares is then:

Squares combined

The squares are then assembled into a 4x4 square, matched up by paths. The path patterns on the edge of the 1x1 squares are shown above (1 = path present, 0 = path absent, in clockwise order). We can deduce the assembly pattern as follows:

1. 0010 matches with 0100, but no 1x1 has 0100 on any edge, so all 0010s must occur on the edge of the 4x4. Thus, the only 8 1x1s that can form part of the center 2x2 are (color coded for how they will be used in parts (2) and (3)):

   Debated	MOOTED	Keanu role	TED	1101	1111	1111	1110
   Shindig	BLOWOUT	Fight	BOUT	1111	1110	0101	1111
   Theseus				1101	0101	1111	1111
   Bridge unit	SMOOT	Ave. crosser	ST.	0001	1001	0110	1001
   Dinero	MOOLA	Sol follower	LA	0110	0001	0110	1001
   Luna	THE MOON	At that time	THEN	1000	1000	1011	1011
   Sacred	HALLOWED	Dragged	HALED	0111	0111	1000	1000
   Scram	VAMOOSE	Urn	VASE	1010	1000	1000	1010

2. ST and LA only have one edge apiece (0001) that matches anything else in this set (the 1000 of THEN, HALED, and VASE), so if either one occurs in the central 2x2, they both have to, next to each other, touching two of THEN, HALED, and VASE at their 0001 edges; but then a 0110 of LA would be touching a 1001 of ST, which is impossible. Thus, ST and LA are not in the central 2x2.

3. Also, none of THEN, HALED, and VASE can touch each other, so if there is more than one of these in the central 2x2 there would have to be two, catercorner, touching two of TED, BOUT, and Theseus; however, TED cannot touch VASE, BOUT cannot touch THEN, and Theseus cannot touch HALED, so this is impossible. So there cannot be more than one of THEN, HALED, and VASE in the central 2x2, so that 2x2 must consist of one of these along with all of TED, BOUT, and Theseus. Of the six options for neighbors of THEN, HALED, and VASE only one allows the remaining one of TED, Theseus, and BOUT to be placed (orientations are given in parentheses):

   VASE (v)	1010	0101	Theseus (v)		VASE (v)	1010	0101	BOUT (>)
   1010			1101		1010			1110
   0101					0101
   BOUT (v)	1111		X		Theseus (<)	1111		X
   HALED (>)	0111	1110	BOUT (v)		HALED (>)	0111	1110	TED (^)
   0111			1111		0111			1111
   1110					1110
   TED (>)	1101		X		BOUT (<)	0101		X
   THEN (<)	1011	1101	TED (<)		THEN (<)	1011	1101	Theseus (<)
   1011			1110		1011			1111
   1101					1101			1111
   Theseus (^)	0101		X		TED (^)	1111	1111	BOUT (^)

   Up to rotation, we now have the following as the central 2x2, and need to fill in the edge 1x1s:

   	A			B			C			D
   				1000			0101
   	L		1000	THEN (<)	1011	1101	Theseus (<)	1111		E
   				1011			1111
   				1101			1111
   	K		1110	TED (^)	1111	1111	BOUT (^)	1110		F
   				1111			0101
   	J			I			H			G

4. The two 1000s on THEN have to be matched by 0001s that are not adjacent to a 0010. Only ST, LA, and RING have such a 0001. The six possibilities are:

   	0110	0110	LA (>)			1001	1001	ST (v)
   1010			0001		1010			0001
   0101			1000		0101			1000
   RING (^)	0001	1000	THEN (<)		RING (^)	0001	1000	THEN (<)
   	0111	1110	RING (>)			0111	1110	RING (>)
   0110			0001		1001			0001
   0110			1000		1001			1000
   LA (^)	0001	1000	THEN (<)		ST (>)	0001	1000	THEN (<)
   	0110	0110	LA (>)			1001	1001	ST (v)
   1001			0001		0110			0001
   1001			1000		0110			1000
   ST (>)	0001	1000	THEN (<)		LA (^)	0001	1000	THEN (<)

   Of these, only the last allows any 1x1 to fit into A corner, and only MARE (>) fits there.

5. The B-C edge is now 1001-1001, and the L-K edge is now 0110-0110, so HOLLY (<) must be in C and CAL (v) must be in K. Also, E and I must contain the only two remaining 1x1s with a 1111 edge, FER and WILY. Putting FER (<) in I and WILY (^) in E leaves no possibilities for F and H. Putting FER (v) in E and WILY (>) in I forces F to be HALED (v) and H to be VASE (^). Up to rotation, we now have:

   	0010			0110			0010
   0101	MARE (>)	1001	1001	ST (v)	1001	1001	HOLLY(<)	1000		D
   	0110			0001			1010
   	0110			1000			0101			1010
   1001	LA (^)	0001	1000	THEN (<)	1011	1101	Theseus (<)	1111	1111	FER (v)	0010
   	0110			1011			1111			0001
   	0110			1101			1111			1000
   0010	CAL (v)	0111	1110	TED (^)	1111	1111	BOUT (^)	1110	0111	HALED (v)	1000
   	0111			1111			0101			0111
   				1111			1010
   	J		1000	WILY (>)	0101	1010	VASE (^)	1000		G
   				0010			1000

6. Finally, CHER's 1110 and 0001 are not adjacent, so it cannot go in J or G and must go in D as CHER (>), RING's 1110 is clockwise from its 0001, so it cannot go in J and must go in G as RING (v), and finally by elimination the Damsel must go in J as Damsel (^). As per the instructions, the Damsel needs to be upright; here, since she already is upright, we do not need to rotate the 4x4 further. The final, assembled 4x4 is:

   

We can now trace a path from Theseus, through all the minotaurs, to the damsel and out of the labyrinth. This path crosses the Latin word VIR on leaving Theseus, and for everyone else crosses a cluster of one or two consonants on arriving and a vowel on leaving; putting these consonants and vowels together, in path order, we have the following:

Each of the consonant(s)-vowel combinations is the conventional spelling of a syllable represented by a character in Linear B (a system for writing Greek, originating on Crete, that predates the Greek alphabet); VIR is the conventional name for the Linear B ideogram for "man." Taking these Linear B characters, in the same orientations as the figures, along the path, we have:

forming the clue KATE IN THE COWBOYS; the answer is the actress who played Kate in the 1972 film The Cowboys, COLLEEN DEWHURST.